a boy pushed horizontally a 3.5 kg brainly
1. a boy pushed horizontally a 3.5 kg brainly
Answer:
i'don't know im sorry po
Explanation:
byee salamats sa points byee anniyong
2. 3.Solve for the acceleration of a 5 kg box being pushed by a boy with 20 N?
Answer:
4m/s2
Explanation:
F=ma
20N=5kg(a)
Divide both side by 5.
The answer is 4.
acceleration has a unit of m/s2
Answer:
4
Explanation:
=
20=5()
5.
3. A boy pushes horizontally on a 5.5 kg box with a force of 500 N. The cart moves a horizontal distance of 7.5 m.What is the final speed of the box if it started from rest?
Answer:
90.90
Explanation:
4. A boy pushed horizontally a 5 kgplastic chair across the slipperyfloor. If the acceleration of thePlastic chair is 2 m/s2 to the leftWhat is the net force exertedon the plastic chair?Another one ASAP
Answer:
4 m
Explanation:
5. 37. A 5 kg box on a horizontal table is pushed by a horizontal force of 15 N as shown on the right. If the coefficient of friction is 0.4, will the box move? 5 kg K... 15 N
Answer:
ano po grade nyo?
Explanation:
di ko yan kaya ehh
6. A boy pushed horizontally a 7.2 kg plastic chair across the slippery floor. If the acceleration of the plastic chair is 4.5 m/s2 to the left, what is the net force exerted on the plastic chair?
PROBLEM:
A boy pushed horizontally a 7.2 kg plastic chair across the slippery floor. If the acceleration of the plastic chair is 4.5 m/s2 to the left, what is the net force exerted on the plastic chair?Answer: 32.4
Formula: F = ma
F = m × a m = 7.2 kg a = 4.5 m/s²F = ?[tex]F:\:m\:\times\:a\\\\F=32.4[/tex]
➸ Therefore, the net force exerted on the plastic chair is 32.4.
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7. a boy push horizontally at 3.5 kg plastic chair across the slippery + if the acceleration of the a plastic chair is 2.2 m to the left what is the net force exerted on the plastic chair blank
Answer:
Given: m=3.5kg, a=2.2m/s^2 to the left
Solution: F=ma
=(3.5kg)(2.2m/s^2)
=7.7N or 7.7kg·m/s^2 to the left
Hope this helps!
8. a 50 kg table is pushed by a horizontal a horizontal force of 40N for 3s. what is the velocity of the table at the end of 3s
Answer:
neeed points tnx for understanding
9. a 60-kg boy pushes a 120 box. can a boy move the box?[
Answer:
No.. Because the box is 2x the weight of the boy..
10. Calculate the acceleration if you push a 2-kg block on a horizontal floor with a 20N horizontal force.
Answer:
Without the frictional force:
F = ma
20 = 2a
a = 20 / 2
a = 10 m/s^2
With the frictional force:
F = ma
20 - 4 = 2a
16 = 2a
a = 16 / 2
a = 8 m/s^2
Explanation:
Physics
11. A boy pushes horizontally on a 5.5 kg box with a force of 500 N. The cart moves a horizontal distance of 7.5 m.What is the final speed of the box if it started from rest?
Answer:
The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).
12. a boy pushed horizontally a 7-kg table across the floor. if the chair accelerate at 1 .2m/s² to the right what the force exerted on the table given:. solution:
Answer:
8.4 N
Explanation:
m= 7kg
A= 1.2 m/s²
F= ?
kg × m/s² = N
13. a boy pushed horizontally a 4.5 kg. cart across the supermarket .if the acceleration of the cart is 3.2 m/s2 to the right .what is the net force exerted on the cart.
Answer:
14.4 N
Explanation:
F = ma
F = (4.5 kg)(3.2 m/s²)
F = 14.4 N
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14. a 5,000 kg stone is pulled by a boy a horizontally
Answer:
not true
Explanation:
i wish it was true
15. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. If the acceleration of the plastic chair is 2.2 m/s2 to the left, what is the given mass in the problem? *
Answer:
m = 3.5kg
a= 2.2m/s^2, to the left
Find : Force (N)
Formula = F=ma
Answer = 7.7N
16. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. If the acceleration of the plastic chair is 2.2 m/s2 to the left, what is the net force exerted on the plastic chair?
Answer:
m = 3.5kg
a= 2.2m/s^2, to the left
Find : Force (N)
Formula = F=ma
Answer = 7.7N
17. A boy pushed horizontally a 3.5 kg plastic the slippery floor.If the acceleration of the plastic chair is 2.2 m/s² to the left, what is the net force exertd on the plastic chair?
iyo para maalala ang pangunahing
18. calculate the acceleration if you push a 2-kg block on a horizontal floor with a 20-N horizontal force.
Answer:
picture please
Explanation:
picture please
19. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor.if the acceleration of the plastic chair is 2.2 m/s² to the left,what is the net force exerted on the plastic chair?
Answer:7.7 Net Force ( N )
Explanation:
(GRESA Method)
Given - m = 3.5kg a = 2.2 m/s²
Required - Fnet?
Equation (formula) - Fnet = m × a
Solution - Fnet = 3.5kg × 2.2 m/s²
Answer - 7.7 N
Hope it helps
20. A boy pushed horizontally a 4.5 kg plastic chair across the slippery floor. Ifthe acceleration of the plastic chair is 3.2 m/s2 to the left, what is the net forceexerted on the plastic chair?
Answer:
Answer = 7.7N
Step-by-step explanation:
m = 3.5kg
a= 2.2m/s^2, to the left
Find : Force (N)
Formula = F=ma
21. A 10 kg block is pushed across a horizontal surface with a horizontal force of 20 N against an opposing force of 5 N. The acceleration of the block is?
Answer:
15 acceleration of the blocks
Explanation:
PA BRAINLIEST PO HEHE:)
22. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. If the acceleration of the plastic chair is 2.2 m/s2 to the left, what is the net force exerted on the plastic chair?
F = 7.7N
that is my answer
23. a boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. If the acceleration of the plastic chair is 2.2 m/s² to the left, what is the net force exerted on the plastic chair?
Newton's Third Law: The Law of Action and Reaction
Based on the case study, it can be concluded that it includes Newton's 3rd law, so used the formula F = m x a.
Given:
m = 3.5 kg
a = 2.2 m/[tex]s^{2}[/tex]
So,
F = m x a
= 3.5 kg x 2.2 m/[tex]s^{2}[/tex]
= 7.7 N
Newton's 3rd Law Newton's 3rd law states, every action will cause a reaction. If one object exerts a force on another object, the object receiving the force will exert a force equal to the force received from the first object, but in the opposite direction. From this law, it is known that every action has a consequence that gives rise to a reaction, or it can be said that there is cause and effect. Giving a causal force produces an effect force. Action and reaction forces act in opposite directions and act on different objects.
Newton's 3rd Law formula there are three types
Friction formula: Fg = μ x Nwhere Fg = weight / downward force (N)
μ = coefficient of friction
N= Normal force (N).
The formula for gravity: w = m x gwhere w = weight / downward force (N)
m = mass of the object (kg)
g = gravity (m/[tex]s^{2}[/tex])
Specific gravity formula: s = ρ x gwhere
s = Specific gravity (N/[tex]m^{3}[/tex])
ρ = density (kg/[tex]m^{3}[/tex])
g = weight / downward force (N).
In the case of an object on a smooth floor, it is pushed or pulled with a force of F as shown in the figure below. Basically, objects that are pulled or pushed horizontally have the same concept called the direction of the force F both to the right. Because the plane is slippery, when a horizontal force is applied to the right, the object will move to the right so that the direction of the object's displacement is also to the right.
Since the direction of displacement is to the right, the force that is directed to the right is positive. By using Newton's Law, the resultant force acting on the X-axis and Y-axis is as follows.
Resultant force on Y-axis
Fy = m x a
N – w = m x a
because the object is not moving on the Y-axis then a = 0, so
N – w = 0
N = w
Thus the magnitude of the normal force will be equal to the weight of the object, so we can write the equation as follows.
N = w = m x g
Resultant force on the X-axis
Fx = m x a
F = m x a
From the above equation, we can determine the formula for the acceleration of an object that is given a horizontal force on a slippery floor as follows.
a = F x m
where:
N = Normal force (N)
w = weight / downward force (N)
F = Force (N)
m = Mass of object (kg)
a = acceleration of the object (m/[tex]s^{2}[/tex])
g = Earth's gravitational acceleration (m/[tex]s^{2}[/tex])
What is newtons 1st law of motion https://brainly.ph/question/2193616
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24. The bowling4. A boy pushes on a 50 kg box andforce does the boy push on theA. 600 kgB. 600 m/sWhat is the acceleration ofith a force of 25 N?
Answer:
B po ang answer
b po ang answer
25. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor, ifthe acceleration of the plastic chair is 2.2 m/s to the left, what is the net forceexerted on the plastic chair?
Answer:
7.7 N
Explanation:
i hope it will help:)
Answer:7.7
Explanation:
26. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. if the acceleration of the plastics chair is 2.2m/s² to the left what is the net force exerted on the plastic chair?
Answer:
7.7N
Explanation:
G:m=3.5kg acceleration=2.2m/s²
R:F=?
E:F=mxa
S:F=(3.5kg)(2.2m/s²)
A:F=7.7N
27. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. Ifthe acceleration of the plastic chair is 2.2 m/s2 to the left, what is the net forceexerted on the plastic chair?
Answer:
7.7 N
Step-by-step explanation:
F= (3.5 kg) (2.2 m/s^2)
=7.7 N
Formula:
F=ma
28. A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor . If the acceleration of the plastic chair is 2.2 m/s² to the left , what is the net force exerted on the plastic chair?
Answer:
Given: m= 3.5 kg
a= 2.2 m/s2, to the left
F=(3.5 kg)(2.2 m/s2)= 7.7 kg . m/s2 or 7.7N , to the left
29. Calculate the acceleration if you push a 3-kg block on a horizontal floor with a 50-N horizontal force. What acceleration occurs if the friction is 5N?
Answer:
nakikita moba yon alin? nasayong harapan asan ah basta lumingon kna lng
30. calculate the acceleration you push 2-kg dock on a horizontal floor with 2-n horizontal force
Given; a = ?
m = 2 kg
F = 2 N
formula; a = F/m
= 2 N/2 kg
= 1 m/s squared
